Re: GDB 6.1 "frozen"

[David Carlton <carlton@kealia.com>]

On Thu, 25 Mar 2004 17:48:19 -0500, Andrew Cagney <cagney@gnu.org> said:

> I've got:
> - TUI doco (which should go in tomorrow)
> - this GNU/Novell PPC 64 build problem

> but I think that will be resolved in the next 24 hours.

I thought we still had disagreements over PROBLEMS: at the very least,
we should apply the following patch or some variant thereof.

David Carlton
carlton@kealia.com

2004-03-25  David Carlton  <carlton@kealia.com>

	* PROBLEMS: Refer to gdb/1588 instead of gdb/826.

Index: PROBLEMS
===================================================================
RCS file: /cvs/src/src/gdb/PROBLEMS,v
retrieving revision 1.23.2.3
diff -u -p -r1.23.2.3 PROBLEMS
--- PROBLEMS	25 Mar 2004 21:20:26 -0000	1.23.2.3
+++ PROBLEMS	25 Mar 2004 23:48:41 -0000
@@ -15,11 +15,6 @@ the abortion is displayed only after the
 
 *** C++ support
 
-gdb/826: variables in C++ namespaces have to be enclosed in quotes
-
-When referring to a variable in C++ code that is inside a
-namespace, you have to put it inside single quotes.
-
 gdb/931: GDB could be more generous when reading types C++ templates on input
 
 When the user types a template, GDB frequently requires the type to be
@@ -43,6 +38,18 @@ type is "foobar__Fi.0:Local".
 This applies only to classes where the class type is defined inside a
 function, not to variables defined with types that are defined somewhere
 outside any function (which most types are).
+
+gdb/1588: names of c++ nested types in casts must be enclosed in quotes
+
+You must type
+  (gdb) print ('Foo::Bar') x
+or
+  (gdb) print ('Foo::Bar' *) y
+instead of
+  (gdb) print (Foo::Bar) x
+or
+  (gdb) print (Foo::Bar *) y
+respectively.
 
 gdb/1091: Constructor breakpoints ignored
 gdb/1193: g++ 3.3 creates multiple constructors: gdb 5.3 can't set breakpoints