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* gdb usage help!
@ 2001-04-11  4:05 Vishal Kulshrestha
  2001-04-11  6:52 ` Keith Seitz
  0 siblings, 1 reply; 2+ messages in thread
From: Vishal Kulshrestha @ 2001-04-11  4:05 UTC (permalink / raw)
  To: gdb

Hi,
	Is there a way of letting gdb print all the source code lines as
it executes! Some kind of a script like:

#############
break main
run
while 1
step
end
############

Regards,
Vishal.



^ permalink raw reply	[flat|nested] 2+ messages in thread

* Re: gdb usage help!
  2001-04-11  4:05 gdb usage help! Vishal Kulshrestha
@ 2001-04-11  6:52 ` Keith Seitz
  0 siblings, 0 replies; 2+ messages in thread
From: Keith Seitz @ 2001-04-11  6:52 UTC (permalink / raw)
  To: Vishal Kulshrestha; +Cc: gdb

On Wed, 11 Apr 2001, Vishal Kulshrestha wrote:

> 	Is there a way of letting gdb print all the source code lines as
> it executes!

Well, yes and no. You could step/next forever until the program exits or 
you get a signal/exception. You would need to be careful about stepping 
into shared libraries and system calls, etc, but it could be done with a 
simple (overly simple?) gdb script:

$ cat test.c
#include <stdio.h>

int
main (int argc, char *argv[])
{
   int i;

   for (i = 0; i < 10; i++)
     {
       printf ("i = %d\n", i);
     }

  exit (0);
}

$ gdb -nw -q test
(gdb) b main
Breakpoint 1 at 0x8048492: file test.c, line 8.
(gdb) r
Starting program: /home/keiths/test 

Breakpoint 1, main (argc=1, argv=0xbffffab4) at test.c:8
8	   for (i = 0; i < 10; i++)
(gdb) while 1
 >next
 >f  
 >end
10	       printf ("i = %d\n", i);
#0  main (argc=1, argv=0xbffffab4) at test.c:10
10	       printf ("i = %d\n", i);
i = 0
8	   for (i = 0; i < 10; i++)
#0  main (argc=1, argv=0xbffffab4) at test.c:8
8	   for (i = 0; i < 10; i++)
10	       printf ("i = %d\n", i);
#0  main (argc=1, argv=0xbffffab4) at test.c:10
10	       printf ("i = %d\n", i);
i = 1
8	   for (i = 0; i < 10; i++)
#0  main (argc=1, argv=0xbffffab4) at test.c:8
8	   for (i = 0; i < 10; i++)
10	       printf ("i = %d\n", i);
#0  main (argc=1, argv=0xbffffab4) at test.c:10
10	       printf ("i = %d\n", i);
i = 2
8	   for (i = 0; i < 10; i++)
#0  main (argc=1, argv=0xbffffab4) at test.c:8
8	   for (i = 0; i < 10; i++)
10	       printf ("i = %d\n", i);
#0  main (argc=1, argv=0xbffffab4) at test.c:10
10	       printf ("i = %d\n", i);
i = 3
8	   for (i = 0; i < 10; i++)
#0  main (argc=1, argv=0xbffffab4) at test.c:8
8	   for (i = 0; i < 10; i++)
10	       printf ("i = %d\n", i);
#0  main (argc=1, argv=0xbffffab4) at test.c:10
10	       printf ("i = %d\n", i);
i = 4
8	   for (i = 0; i < 10; i++)
#0  main (argc=1, argv=0xbffffab4) at test.c:8
8	   for (i = 0; i < 10; i++)
10	       printf ("i = %d\n", i);
---Type <return> to continue, or q <return> to quit---

and so on.

Keith


^ permalink raw reply	[flat|nested] 2+ messages in thread

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