"path" does not seem to work correctly

"path" does not seem to work correctly

[Mandar Mitra]

Hello,

I have two versions of a program (called smart):
- one compiled with -g and located in .../src/bin
- the other compiled with -O2 (without -g) and located in .../diropt/bin

The diropt/bin directory comes first on my $PATH, but in my ~/.gdbinit
file, I've re-defined "path" so that the debuggable program comes
first:

(gdb) path
Executable and object file path: .../src/bin:/bin:...:diropt/bin:.

But when I run "gdb smart", or "file smart" inside gdb, it still picks
up the optimized executable from diropt/bin.

(gdb) file smart
Reading symbols from .../diropt/bin/smart...done.

Can someone give me some hint about what I'm doing wrong?

Thanks,
Mandar.

Re: "path" does not seem to work correctly

[Daniel Jacobowitz]

On Tue, Jul 17, 2007 at 03:46:19AM +0000, Mandar Mitra wrote:
> But when I run "gdb smart", or "file smart" inside gdb, it still picks
> up the optimized executable from diropt/bin.

I believe that's what is supposed to happen:

`path DIRECTORY'
     Add DIRECTORY to the front of the `PATH' environment variable
     (the
     search path for executables) that will be passed to your program.
     The value of `PATH' used by GDB does not change.

-- 
Daniel Jacobowitz
CodeSourcery

Re: "path" does not seem to work correctly

[Mandar Mitra]

On 7/17/07, Daniel Jacobowitz <drow@false.org> wrote:
> `path DIRECTORY'
>      Add DIRECTORY to the front of the `PATH' environment variable
>      (the
>      search path for executables) that will be passed to your program.
>      The value of `PATH' used by GDB does not change.

Yes, I suppose I was reading out-of-date documentation from somewhere
on the web that suggested that this would change the path for both gdb
and the program.

Thanks for clearing that up,
Mandar.