Debugging static variable in inlined member function

Debugging static variable in inlined member function

[Peng Yu]

Hi,

I have the following program listed below this email. I can not print
_a in the inlined version. But it is OK to print _a in the non-inlined
version. Can you tell me how to debug the inlined version of _a?

(gdb) s
main () at main.cc:32
32        std::cout << a.a() << std::endl;
(gdb) s
A::a (this=0xbff21077) at main.cc:11
11            std::cout << "inline" << std::endl;
(gdb) n
inline
12            ++ _a;
(gdb) p _a
No symbol "_a" in current context.

Thanks,
Peng

#include <iostream>

#define INLINE

class A {
  public:
    A() { }
#ifdef INLINE
    int a() {
      static int _a = 10;
      std::cout << "inline" << std::endl;
      ++ _a;
      return _a;
    }
#else
    int a();
#endif
  private:
};

#ifndef INLINE
int A::a() {
  static int _a = 10;
  std::cout << "not inline" << std::endl;
  ++ _a;
  return _a;
}
#endif

int main() {
  A a;
  std::cout << a.a() << std::endl;
}

Re: Debugging static variable in inlined member function

[Daniel Jacobowitz]

On Mon, Jan 08, 2007 at 09:55:31AM -0600, Peng Yu wrote:
> Hi,
> 
> I have the following program listed below this email. I can not print
> _a in the inlined version. But it is OK to print _a in the non-inlined
> version. Can you tell me how to debug the inlined version of _a?

GDB support for inlined functions is known to be poor.  GCC's debug
info for inlined functions also has some problems.  There is not much
you can do to work around that.

-- 
Daniel Jacobowitz
CodeSourcery