How not to step into functions called as arguments of another function?

How not to step into functions called as arguments of another function?

[Peng Yu]

Hi,

Suppose I have two functions in C++.

void f(int x);

int g();

If I call "f(g())" in my program, when I want to step into f(), I have
to first step in g() first. I'm wondering whether there is simple way
to step into f() directly without stepping into g()?

Thanks,
Peng

Re: How not to step into functions called as arguments of another function?

[Michael Snyder]

On Wed, 2007-11-21 at 06:11 -0600, Peng Yu wrote:
> Hi,
> 
> Suppose I have two functions in C++.
> 
> void f(int x);
> 
> int g();
> 
> If I call "f(g())" in my program, when I want to step into f(), I have
> to first step in g() first. I'm wondering whether there is simple way
> to step into f() directly without stepping into g()?

Not in one command, but in two:
(gdb) break f
(gdb) continue

Re: How not to step into functions called as arguments of another function?

[Joel Brobecker]

> Not in one command, but in two:
> (gdb) break f
> (gdb) continue

Right, or often people will prefer the temporary breakpoint:

        (gdb) tbreak f
        (gdb) cont

It's actually a good idea to define a user command for that if this
is a common situation for you.

-- 
Joel