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Subject: RE: Getting pissed off by gdb. Please help with stepping in.
Date: Thu, 18 Mar 2010 18:37:00 -0000
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From: "Paul Koning" <Paul_Koning@Dell.com>
To: "Eli Zaretskii" <eliz@gnu.org>, 	"Doug Evans" <dje@google.com>
Cc: <temp@sourceboost.com>, 	<gdb@sourceware.org>
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I'd say it is useful because it matches the documentation.  "s" is
documented as "run until you're at a different source line".  In
foo(bar()), the source line you come to after exit from bar() is the
call to foo(), not the first line of foo -- that would take "s 2".

	paul

> -----Original Message-----
> From: gdb-owner@sourceware.org [mailto:gdb-owner@sourceware.org] On
> Behalf Of Eli Zaretskii
> Sent: Thursday, March 18, 2010 2:31 PM
> To: Doug Evans
> Cc: temp@sourceboost.com; gdb@sourceware.org
> Subject: Re: Getting pissed off by gdb. Please help with stepping in.
>=20
> > Date: Thu, 18 Mar 2010 08:10:41 -0700
> > From: Doug Evans <dje@google.com>
> > Cc: temp@sourceboost.com, gdb@sourceware.org
> >
> > Here's what gdb 7.1 does:
> >
> > (gdb) f
> > #0  bar () at stepout.c:4
> > 4       int bar () { return 1; }
> > (gdb) s
> > foo (x=3D1) at stepout.c:6
> > 6       void foo (int x) { g =3D x; }
> > (gdb)
> >
> > Note that we've stepped out of bar and into foo.
> >
> > Here is what Pavel is expecting instead:
> >
> > (gdb) f
> > #0  bar () at stepout.c:4
> > 4       int bar () { return 1; }
> > (gdb) s
> > 0x00000000004003b7 in main () at stepout.c:11
> > 11        foo (bar ());
> > (gdb)
>=20
> Thanks.  But why is ``what Pavel is expecting'' useful?  What use-case
> does it handle that the v7.1 behavior does not?