Re: How to show instructions in one record

慕冬亮
2016-09-06T15:43:40Z

2016-09-06 11:00 GMT-04:00 Jan Kratochvil <jan.kratochvil@redhat.com>:
> On Tue, 06 Sep 2016 16:13:52 +0200, 慕冬亮 wrote:
>> So how to show instructions in one record?
>
> I do not fully understand what "instructions in one record" mean but some
> demo:
>
I just want all the instructions which have already executed in one
execution path. Take the following demo as example,

What I need is the instruction list:

203 movq %r9, 16(%rdi)
203 movq %r9, 16(%rdi)
202 movq %r8, 8(%rdi)
201 movq %rax, (%rdi)
199 movq 24(%rsi), %r10
198 movq 16(%rsi), %r9
......
If there are loops, I need all the instructions in the loop.
I don't know whether process record/replay could achieve this goal.

> (gdb) start
> [...]
> (gdb) record
> (gdb) c
> Continuing.
> Program received signal SIGINT, Interrupt.
> __memcpy_sse2 () at ../sysdeps/x86_64/memcpy.S:203
> 203 movq %r9, 16(%rdi)
> (gdb) info record
> Active record target: record-full
> Record mode:
> Lowest recorded instruction number is 1.
> Highest recorded instruction number is 100092.
> Log contains 100092 instructions.
> Max logged instructions is 10000000.
> (gdb) reverse-stepi
> 203 movq %r9, 16(%rdi)
> (gdb)
> 202 movq %r8, 8(%rdi)
> (gdb)
> 201 movq %rax, (%rdi)
> (gdb)
> 199 movq 24(%rsi), %r10
> (gdb)
> 198 movq 16(%rsi), %r9
> (gdb) info record
> Active record target: record-full
> Replay mode:
> Lowest recorded instruction number is 1.
> Current instruction number is 100087.
> Highest recorded instruction number is 100092.
> Log contains 100092 instructions.
> Max logged instructions is 10000000.
> (gdb) frame
> #0 __memcpy_sse2 () at ../sysdeps/x86_64/memcpy.S:198
> 198 movq 16(%rsi), %r9
> (gdb) x/i $pc
> => 0x7ffff50311e9 <__memcpy_sse2+217>: mov 0x10(%rsi),%r9
> (gdb) _