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Date: Sun, 23 Dec 2007 02:26:00 -0000
From: "jian shen" <vicshen@gmail.com>
To: "jian shen" <vicshen@gmail.com>, gdb@sourceware.org
Subject: Re: gdb cannot understand some type with STL
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On 12/23/07, Daniel Jacobowitz <drow@false.org> wrote:
> What does "whatis l" print?  I believe this problem is because GDB
> does not know about default template parameters.
>
>  template<typename _Tp, typename _Alloc = std::allocator<_Tp> >
>    class list : protected _List_base<_Tp, _Alloc>
>
> It's going to be a std::list<int, std::allocator<int> > or something
> like that.

You are right.

(gdb) whatis l
type = std::list<int, std::allocator<int> >
(gdb) whatis 'std::list<int, std::allocator<int> >'
type = std::list<int, std::allocator<int> >

>
> This is fixable, but it would require changes to both GCC and GDB that
> no one has worked on yet.
>
> > (gdb) whatis std::list<int>*
> > A syntax error in expression, near `'.
>
> This looks like a bug in GDB, in the c-exp.y parser.

Yes, this looks like a bug.
(gdb) whatis 'std::list<int, std::allocator<int> >*'
No symbol "std::list<int, std::allocator<int> >*" in current context.

Thanks,
Jian