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From: Pedro Alves <palves@redhat.com>
To: Nancy <nancydreaming@gmail.com>, gdb@sourceware.org
Subject: Re: Is that a GDB bug?
Date: Mon, 12 Oct 2015 14:14:00 -0000	[thread overview]
Message-ID: <561BC039.9050708@redhat.com> (raw)
In-Reply-To: <CADdyJmk-gKUVEUYRwqmXPknUL8QiT=x+J6ZA2BL8WjK1Nf+Z3A@mail.gmail.com>

On 10/12/2015 01:46 PM, Nancy wrote:
> Hi,
> 
> Why line 5 execute twice?   Is that a GDB bug?
> 
> debug.c :
>      1    int main()
>      2    {
>      3        int x;
>      4        x=0;
>      5        L1: switch(x) { case 0: x=1; goto L1;  case 1: if(x==0)
> goto L1; else break; }
>      6        x=2;
>      7    }
> 
> $ gcc -O0 -g debug.c -o debug
> $ gdb debug
> GNU gdb (Ubuntu 7.7.1-0ubuntu5~14.04.2) 7.7.1
> Copyright (C) 2014 Free Software Foundation, Inc.
> ....................
> Reading symbols from debug...done.
> (gdb) b 5
> Breakpoint 1 at 0x80483fa: file debug.c, line 5.
> (gdb) r
> Starting program: /mnt/hgfs/cygwin/tmp/debug
> 
> Breakpoint 1, main () at debug.c:5
> 5        L1: switch(x) { case 0: x=1; goto L1;  case 1: if(x==0) goto
> L1; else break; }
> (gdb) n

x starts as 0.  So the fist time, "goto L1" is executed.  That makes execution
flow back to the address where the breakpoint was inserted, so you get another
breakpoint hit:

> 
> Breakpoint 1, main () at debug.c:5
> 5        L1: switch(x) { case 0: x=1; goto L1;  case 1: if(x==0) goto
> L1; else break; }

It doesn't matter that "next" was in progress.  The breakpoint hit takes
priority.

> (gdb) n
> 6        x=2;
> 
> 

Thanks,
Pedro Alves


      parent reply	other threads:[~2015-10-12 14:14 UTC|newest]

Thread overview: 7+ messages / expand[flat|nested]  mbox.gz  Atom feed  top
2015-10-12 12:46 Nancy
2015-10-12 13:20 ` Mike Frysinger
2015-10-12 13:32   ` Andreas Schwab
2015-10-12 16:39     ` Mike Frysinger
2015-10-12 16:56       ` Simon Marchi
2015-10-12 16:59       ` Andreas Schwab
2015-10-12 14:14 ` Pedro Alves [this message]

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