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Date: Fri, 12 Feb 2010 19:10:00 -0000
From: Michael Snyder <msnyder@vmware.com>
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To: Pedro Alves <pedro@codesourcery.com>
CC: "gdb@sourceware.org" <gdb@sourceware.org>,   "Paragi, Ajeykumar B" <ajeykumar.paragi@hp.com>,  "gdb@gnu.org" <gdb@gnu.org>
Subject: Re: gdb command line option -e or -exec usage
References: <RT-Ticket-550483@rt.gnu.org> <E2E3C92B1E0AB4468F79FC237074B248274A4D096D@GVW1116EXC.americas.hpqcorp.net> <4B75A1AD.20908@vmware.com> <201002121858.11192.pedro@codesourcery.com>
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Pedro Alves wrote:
> On Friday 12 February 2010 18:45:01, Michael Snyder wrote:
>> Paragi, Ajeykumar B wrote:
>>> Hi,
>>>
>>> I have invoked gdb with '-e' command line option on an executable, 
>>> The gdb manual says '-e' is used to set the executable to run.
>>> But I could not see the symbols read in by gdb when I use -e and could
>>> not insert breakpoints.
>>>
>>> What is the intent of having the command line option "-e" or "-exec"?
>> Hmmm, it does seem to be broken.
> 
> It's not.  `-e' is equivalent to "(gdb) exec-file".  It doesn't read
> its argument for symbols, only for executable to run, or for pure
> memory contents.
> 
>> You can get the same effect, though, by just leaving out the -e flag.
>>
>>      % gdb my-executable
> 
> That's equivalent to "(gdb) file", which is equivalent to
> "gdb -e my-executable -s my-executable", or just "gdb -se my-executable".
> 

Right!  Thanks, Pedro.