From mboxrd@z Thu Jan  1 00:00:00 1970
Return-Path: <gdb-return-24703-listarch-gdb=sources.redhat.com@sourceware.org>
Received: (qmail 12990 invoked by alias); 31 Mar 2006 07:36:07 -0000
Received: (qmail 12982 invoked by uid 22791); 31 Mar 2006 07:36:06 -0000
X-Spam-Check-By: sourceware.org
Received: from uproxy.gmail.com (HELO uproxy.gmail.com) (66.249.92.207)     by sourceware.org (qpsmtpd/0.31) with ESMTP; Fri, 31 Mar 2006 07:36:05 +0000
Received: by uproxy.gmail.com with SMTP id m2so337522ugc         for <gdb@sourceware.org>; Thu, 30 Mar 2006 23:36:02 -0800 (PST)
Received: by 10.66.252.9 with SMTP id z9mr69664ugh;         Thu, 30 Mar 2006 23:36:02 -0800 (PST)
Received: from ?192.168.1.151? ( [82.24.24.234])         by mx.gmail.com with ESMTP id m1sm587022uge.2006.03.30.23.36.02;         Thu, 30 Mar 2006 23:36:02 -0800 (PST)
Message-ID: <442CCE46.7080800@gmail.com>
Date: Fri, 31 Mar 2006 08:19:00 -0000
From: Bill Pursell <bill.pursell@gmail.com>
User-Agent: Mozilla Thunderbird 1.0.7-1.1.fc3 (X11/20050929)
MIME-Version: 1.0
To: Jim Blandy <jimb@red-bean.com>
CC:  gdb@sourceware.org
Subject: Re: scope in nested function
References: <442CC4BB.5070709@gmail.com> <8f2776cb0603302257t14f38361ibf8ab1cb74dfb774@mail.gmail.com>
In-Reply-To: <8f2776cb0603302257t14f38361ibf8ab1cb74dfb774@mail.gmail.com>
Content-Type: text/plain; charset=ISO-8859-1; format=flowed
Content-Transfer-Encoding: 7bit
X-IsSubscribed: yes
Mailing-List: contact gdb-help@sourceware.org; run by ezmlm
Precedence: bulk
List-Subscribe: <mailto:gdb-subscribe@sourceware.org>
List-Archive: <http://sourceware.org/ml/gdb/>
List-Post: <mailto:gdb@sourceware.org>
List-Help: <mailto:gdb-help@sourceware.org>, <http://sourceware.org/ml/#faqs>
Sender: gdb-owner@sourceware.org
X-SW-Source: 2006-03/txt/msg00230.txt.bz2

Jim Blandy wrote:
> On 3/30/06, Bill Pursell <bill.pursell@gmail.com> wrote:
> 
>>I'm not sure how to reference a variable in a nested function from gdb.
>>In the gdb session below, there are 2 things I don't understand
>>how to do:
>>
>>1) how do I set a breakpoint in foo? (other than by referencing a line
>>        number)
> 
> 
> Have you tried calling it main::foo?
> 
> 
>>2) when I'm in foo, how do I reference i?
> 
> 
> Have you tried calling it main::i?
> 
> I'm not sure these will work, but I think they're supposed to.
> 

I get the error:
Can't find member of namespace, class, struct, or union named "main::foo"

Same for main::i