From: Jan Kratochvil <jan.kratochvil@redhat.com>
To: hex <heixia108@gmail.com>
Cc: gdb@sourceware.org
Subject: Re: Could GDB get offset of a field in virtual base class through NULL pointer
Date: Mon, 30 Sep 2013 08:16:00 -0000 [thread overview]
Message-ID: <20130930081626.GA15265@host2.jankratochvil.net> (raw)
In-Reply-To: <CAB_AMN5ngrKWwwVwUBFQ1wS5fLiDCyDRO+qe9bOjPBJAMo-05Q@mail.gmail.com>
On Sun, 29 Sep 2013 03:59:54 +0200, hex wrote:
> > I do not see what it should do. In the following case &(((B *)&OBJECT)->a)
> > prints once 12 and once 16 for different OBJECT so what it should print for 0?
> >
> > class X:public virtual A,public B {};
> > class C {
> > public:
> > int c;
> > };
> > class Y:public virtual A,public C,public B {};
> > #include <iostream>
> > int main() {
> > X x;
> > Y y;
> > std::cout << (char *)&(((B *)&x)->a)-(char *)&x << std::endl;
> > std::cout << (char *)&(((B *)&y)->a)-(char *)&y << std::endl;
> > }
> >
>
> If we use &(((B *)0)->a), we are likely to get offset of 'a' in class
> B. If GDB could
> support this specific case, we do not need a real object to get the offset.
This would apply if you had s/virtual A/A/. But with the inheritance of
A being virtual the memory location of A inside the whole object instance is
"random", it does not depend on B but it depends on X or Y. Specifically it
depends on virtual tables used for the specific instance, the virtual tables
specify the location of A. This is what I am trying to show you in the
example above.
The same expression (char *)&(((B *)&OBJECT)->a) produces different result
depending on which OBJECT you pass there. Therefore which result should
produce passing 0 instead of &OBJECT there? It cannot be a single number.
Jan Kratochvil
next prev parent reply other threads:[~2013-09-30 8:16 UTC|newest]
Thread overview: 5+ messages / expand[flat|nested] mbox.gz Atom feed top
2013-09-28 16:23 hex
2013-09-28 18:39 ` Jan Kratochvil
2013-09-29 1:59 ` hex
2013-09-30 8:16 ` Jan Kratochvil [this message]
2013-09-30 14:29 ` hex
Reply instructions:
You may reply publicly to this message via plain-text email
using any one of the following methods:
* Save the following mbox file, import it into your mail client,
and reply-to-all from there: mbox
Avoid top-posting and favor interleaved quoting:
https://en.wikipedia.org/wiki/Posting_style#Interleaved_style
* Reply using the --to, --cc, and --in-reply-to
switches of git-send-email(1):
git send-email \
--in-reply-to=20130930081626.GA15265@host2.jankratochvil.net \
--to=jan.kratochvil@redhat.com \
--cc=gdb@sourceware.org \
--cc=heixia108@gmail.com \
/path/to/YOUR_REPLY
https://kernel.org/pub/software/scm/git/docs/git-send-email.html
* If your mail client supports setting the In-Reply-To header
via mailto: links, try the mailto: link
Be sure your reply has a Subject: header at the top and a blank line
before the message body.
This is a public inbox, see mirroring instructions
for how to clone and mirror all data and code used for this inbox