Re: Watchpoints with condition

Jim Blandy
2007-12-05T21:37:02Z

Michael Snyder <msnyder at specifix.com> writes:
> On Tue, 2007-12-04 at 09:23 -0800, Jim Blandy wrote:
>> Michael Snyder <msnyder at specifix.com> writes:
>> > On Tue, 2007-12-04 at 06:23 +0200, Eli Zaretskii wrote:
>> >> > Cc: gdb@sourceware.org
>> >> > From: Jim Blandy <jimb@codesourcery.com>
>> >> > Date: Mon, 03 Dec 2007 15:07:19 -0800
>> >> >
>> >> > In the use case you mention, why wouldn't 'watch v == X'; 'watch v ==
>> >> > Y'; etc. have worked for you? You would have gotten more hits than
>> >> > you'd like, but only twice as many --- is that right?
>> >>
>> >> It would have shown me hits I don't want to see, yes. And it is more
>> >> natural to write "watch X if X == 1" than what you suggest.
>> >
>> > I have to agree -- typing "watch X == 1" is intuitive to you and me
>> > (because we're gdb hackers), but it would not be intuitive to most
>> > users. Besides, as Eli says, it gives you unwanted hits. Why would
>> > we want to explain all of that (including the unwanted hits) to a
>> > naive user?
>>
>> I guess I don't see why 'GDB stops your program whenever the value of
>> this expression changes' is hard to understand. Explaining
>> conditional watchpoints is a superset of explaining watchpoints, so I
>> don't see how it could be simpler.
>
> Well, since eliminating conditional watchpoints is not on the table,
> I guess it's a moot point, eh?

Hey, I did shrug. :)