Re: GDB C++ support

[Daniel Jacobowitz <drow@mvista.com>]

On Tue, Jan 15, 2002 at 11:48:34AM -0600, Michael Elizabeth Chastain wrote:
> eli> You don't need to apologize about not having the information I asked
> eli> for.  But there's no need to be harsh, either.
> 
> Yeah, you're right, I got up grouchy this morning.  I apologize for that.
> 
> Co-incidentally, I'm making test runs with stock 5.1 right now.
> Here's an excerpt from gdb.log:
> 
>   # gdb 5.1, gcc 3.0.2, -gdwarf-2, gdb.c++/method.exp
> 
>   (gdb) break main^M
>   Breakpoint 1 at 0x8048549: file /berman/migchain/source/gdb-5.1/gdb/testsuite/gdb.c++/method.cc, line 66.^M
>   (gdb) run ^M
>   Starting program: /berman/migchain/build/native/gdb-5.1/gdb/testsuite/gdb.c++/method ^M
>   ^M
>   Breakpoint 1, main () at /berman/migchain/source/gdb-5.1/gdb/testsuite/gdb.c++/method.cc:66^M
>   66        k = 10;^M
>   (gdb) break A::foo^M
>   Breakpoint 2 at 0x80484a6: file /berman/migchain/source/gdb-5.1/gdb/testsuite/gdb.c++/method.cc, line 38.^M
>   (gdb) PASS: gdb.c++/method.exp: set breakpoint on A::foo
>   continue^M
>   Continuing.^M
>   ^M
>   Breakpoint 2, A::foo(int) (this=0xbffff0e0, arg=13) at /berman/migchain/source/gdb-5.1/gdb/testsuite/gdb.c++/method.cc:38^M
>   38        x += arg;^M
>   (gdb) FAIL: gdb.c++/method.exp: continuing and breaking in A::foo
> 
> So you can see that 'break A::foo' works and gdb takes the breakpoint.
> I don't know what that "FAIL" is about (that is a different issue).

Probably the fact that the name of the function is 'A::foo(int)'.  I
fixed this in the testsuite on the trunk (or Jason did; I don't
recall).

-- 
Daniel Jacobowitz                           Carnegie Mellon University
MontaVista Software                         Debian GNU/Linux Developer