Re: How to call operator<< functions?

Daniel Jacobowitz
2006-08-30T20:54:25Z

On Wed, Aug 30, 2006 at 11:45:33PM +0300, Michael Veksler wrote:
> Great progress. The most annoying and common failures I have used to be
> seeing is no more.

I will test and commit the patch (but not right this moment).

> The other annoying issues sorted by decreasing annoyance :
> - this->Print is not always found (I'll try to create a small test-case
> later).

I think my other changes will help here, though I'm not sure.

> - std::cout related crashes

Fred's pegged this one I suspect. This is a serious bug and we need to
fix it, but it will be a bit tricky.

> - print myCout << x --- won't work need to resort to
> print 'operator<<........'(myCout, x)

I think that foo::operator<< is supported, but operator<<(foo&,...)
isn't. Or else something's wrong with the support.

--
Daniel Jacobowitz
CodeSourcery