From mboxrd@z Thu Jan 1 00:00:00 1970 Return-Path: Received: (qmail 20520 invoked by alias); 22 Oct 2003 20:04:50 -0000 Mailing-List: contact gdb-patches-help@sources.redhat.com; run by ezmlm Precedence: bulk List-Subscribe: List-Archive: List-Post: List-Help: , Sender: gdb-patches-owner@sources.redhat.com Received: (qmail 20494 invoked from network); 22 Oct 2003 20:04:48 -0000 Received: from unknown (HELO zenia.home) (12.223.225.216) by sources.redhat.com with SMTP; 22 Oct 2003 20:04:48 -0000 Received: by zenia.home (Postfix, from userid 5433) id 4B11120766; Wed, 22 Oct 2003 15:04:38 -0500 (EST) To: Andrew Cagney Cc: gdb-patches@sources.redhat.com, Kris Warkentin , Daniel Jacobowitz Subject: Re: RFA: osabi: correct test for compatible handlers References: <3F96D128.5040904@redhat.com> From: Jim Blandy Date: Wed, 22 Oct 2003 20:04:00 -0000 In-Reply-To: <3F96D128.5040904@redhat.com> Message-ID: User-Agent: Gnus/5.09 (Gnus v5.9.0) Emacs/21.3 MIME-Version: 1.0 Content-Type: text/plain; charset=us-ascii X-SW-Source: 2003-10/txt/msg00657.txt.bz2 Andrew Cagney writes: > > + /* BFD's 'A->compatible (A, B)' functions return zero if A and B are > > + incompatible. But if they are compatible, it returns the 'more > > + featureful' of the two arches. That is, if A can run code > > + written for B, but B can't run code written for A, then it'll > > + return A. > > + + struct bfd_arch_info objects are atoms: that is, there's > > supposed > > + to be exactly one instance for a given machine. So you can tell > > + whether two are equivalent by comparing pointers. */ > > + return (a == b || a->compatible (a, b) == a); > > Hey, nice. > > Don't worry about a can_run_code_for function though, having the logic > inline makes what's happening easier to understand (and will simplify > a follow-on wild-card patch I've got pending). It may be easier for you, but the original author did get the test backwards, and I had to go through an embarrassing number of wrong tries before I got it right. I'd really like to leave the function separate.