Re: Watching expressions that don't involve memory (e.g., watch $regfoo)

Eli Zaretskii
2010-03-04T14:11:34Z

> From: Pedro Alves <pedro@codesourcery.com>
> Date: Thu, 4 Mar 2010 13:16:29 +0000
>
> On Thursday 04 March 2010 04:12:19, Eli Zaretskii wrote:
> > > From: Pedro Alves <pedro@codesourcery.com>
> > > Date: Thu, 4 Mar 2010 01:56:44 +0000
> > >
> > > Anyone else things this is useful?
> >
> > I do. (Somehow, I thought it actually did work at some point in the
> > past, but maybe I was dreaming.)
>
> Indeed, I tried it on 5.3 and 6.0 gdbs, and it worked. Looking
> at the code, I guess it broke with the support for
> multi-location breakpoints, in 6.8. I guess I shall drop the
> NEWS entry, as it's a regression fix afterall?

There's nothing wrong with saying "works again", if it was broken for
a long time. But if it became broken in 6.8, maybe it's not enough
time.

> I think I'll add a simple test that watches for "watch $pc",
> so that we don't regress again.

Yes, thanks.